The Thevenin Theorem explains how to simplify a complex circuit. It states that any linear circuit with only voltage sources, current sources and resistors can be simplified to a voltage source with a series resistor.
But what does this really mean?
Sometimes a picture says more than thousand words, so here are two pictures to explain what Thevenin’s Theorem is about.
…can be represented by this simple circuit
How to use Thevenin’s Theorem
To get from the complex circuit to the simple Thevenin equivalent we:
- Calculate the Thevenin equivalent voltage between terminals A-B open circuited
- Calculate the Thevenin equivalent resistance between terminals A-B with all current sources open circuited and all voltage sources short circuited
Finding the Thevenin Equivalent Voltage
First we’ll find the equivalent voltage.
We see that R4 makes a voltage divider together with R3 and R2. Since R4 = R2 + R3 the voltage will be divided in half on the right side of R4.
Since A is not connected to anything, no current will pass through R1 and therefore no voltage drop will occur over R1. So terminal A is 7.5 V.
Finding the Thevenin Equivalent Resistance
Then, let’s find the equivalent resistance.
First, we short-circuit the voltage source. This puts R4 in parallel with R2+R3. We calculate this and get 1k Ohm. This is in series with R1 (also 1k Ohm), so we get an equivalent resistance of 2k Ohms.
Then we put these two together and get the following Thevenin equivalent circuit:
What do you use the Thevenin equivalent circuit for?
The Thevenin theorem is really useful for doing calculations with circuits. If you have a complex circuit, you can simplify it and make calculations much easier.
But, I have to admit that I can’t remember ever having applied this outside of a classroom though