Do you want to build a circuit that blinks a light? This inverter-based circuit is simple, and it’s small enough to fit on a breadboard.
The circuit uses standard basic electronic components and you can build it even if you have never built anything before. Check out the full build instructions in the video below:
Scroll down to find the complete circuit diagram, component list, and step-by-step instructions (in text-form) on how to build this circuit.
The Circuit Diagram
In the lessons, you learned that you needed an inverter for this circuit. But there’s one important point if you want to build this:
You need to use a Schmitt-triggered inverter. It’s an inverter where the voltage at which it switches from LOW to HIGH is higher than the voltage for switching from HIGH to LOW.
You’ll find the complete circuit diagram below.
The numbers next to each pin in the diagram represent the pin number on the integrated circuit. Click here for the pinout of the Hex Schmitt Trigger Inverter IC.
The Components You Need
| Part | Value | Note |
|---|---|---|
| – | Breadboard | Breadboard |
| – | 2 x Jumper Wires | Any stiff wire (22-23 AWG) |
| – | 9V Battery clip | To connect battery to board |
| BATT1 | 9V Battery | To power the circuit |
| U1 | 74C14 or CD40106 | Hex Schmitt Trigger Inverter |
| C1 | 100μF | Polarized capacitor |
| R1 | 10 kΩ | Any resistor type |
| R2 | 10 kΩ | Any resistor type |
| LED1 | Red | Standard LED (low power) |
These are pretty standard components that you can get from most places that sell parts for building electronics. I’ve created a page with a list of where to buy electronic components here.
Build The Circuit Step-by-Step
When you have the components in hand, you’re ready to build the circuit.
Not sure how the breadboard works? Then you might want to read How To Use a Breadboard first.
Step 1: Place the Integrated Circuit (U1)
Start with U1, the Hex Schmitt Trigger Inverter IC. Place it across the gap in the middle, with pin 1 in the upper left corner.
Step 2: Place the Capacitor (C1)
Next, place the capacitor C1. First, find the negative pin. It should be marked with minus or zero. Often the negative pin is shorter than the positive pin.
Connect the negative pin in the negative supply column. And connect the positive pin to the same row as Pin 1 of the IC.
Step 3: Place the Resistor (R1)
The resistor R1 should go from the input (Pin 1) to the output (Pin 2). Bend the legs of the resistor so that you can connect it from the row of Pin 1 to the row of Pin 2.
Step 4: Place the LED (LED1)
Next, connect the LED. The negative leg of the LED is the shortest one. Connect it to the negative supply column. Connect the longer leg to an empty row.
Step 5: Place the Resistor (R2)
The resistor R2 connects the output (Pin 2) to the LED. Place one leg of the resistor into the row of Pin 2. Place the other leg on the same row as the long leg of the LED.
Step 6: Connect GND to Minus
The GND (Pin 7) of the IC must be connected to ground. In this circuit, ground is the minus of the battery. Connect one end of a jumper wire to the same row as Pin 7. Connect the other end to the negative supply column.
Step 7: Connect VDD to Plus
The VDD (Pin 14) of the IC must be connected to the positive supply. Connect one end of a jumper wire to the positive supply column. Connect the other end to the same row as Pin 14.
Step 8: Connect the Battery
Finally, connect the red wire from the battery to the positive supply column. And connect the black wire to the negative supply column.
Your LED should start to blink.
Questions?
Did you build it? How did it go?
Let me know in the comments below.
Ed says
Hi
I’m looking to build a Star Trek TNG TRICORDER light and sounds,
But I’m not sure how to do it. Any information you could share, would be much appreciated. Or where I could find that information. They used to sell them on eBay, but I cannot find any.
bruce hull says
still struggling with the blinking light. My energy source is a solar light for area lighting with a 3.7 volt Li-ion 800 mAh rechargeable battery. it’s currently reading 2.11 volts. I’m not sure on the pin outs of the inverter. Actually I would love a pin out on the schematic.
Bruce says
Great information. I’m looking to have a LED blink but I want the LED to slowly light and then slowly go off. In a two second cycle loop. Any suggestions?
ArpitaS says
Maybe use a adruino board?
Ajaz Amin says
U can use a dimmer led instead but that will blink rapidly and slowly light off
AlbeOutlaw176 says
Yes I have a Comment why don’t you build it step by step show how to build it not just to show it light up ?
admin says
I just updated the article with step by step instructions. Hope you’ll find it useful!
bruce hull says
OK, list the parts and where I can get them. I would have loved this sixty years ago but right now I want to finish my prioject AND I do see future projects that wil required me to dig a bit deeper.
admin says
Hi Bruce,
Here’s a page with several options on where to buy the components from:
https://www.build-electronic-circuits.com/buy-electronic-components/
Best,
Oyvind
Niladri Patra says
Hi,
I want to make 3v LED Flash light with LDR.
This type of light is using fishing purpose in sea.
Regards
Niladri
Ben says
I am still unsure about how the voltage interacts with the inverter. If I track the current, it leaves the positive pole of the 9V and travels directly to the inverter (at the input labelled 14). I assumed that this was the power supply to the inverter and would be constant. And that this voltage would exit through the output labelled ‘7’ and return to the battery. Is this an activating voltage that would then cause the inverter (with no initial voltage at the input labelled ‘1’) to output a voltage at ‘2’, which would loop around and cause the inverter to switch, initiating the on/off loop? Sorry if this is confusing…
admin says
The pins 14 and 7 are for powering the inverter. When the output is HIGH, it’s from here the output gets its voltage and current, yes.
bruce hull says
OK…update. I triple checked the schematic and used a couple of combinations. First I used a 9 Volt battery with the solar light and later on LED and in both setups I got a strong resulting illumination. I then used the solar panel with the 2.1 volts with both LET setups and got a average illumination result. The appears to be a slight flickering of the lights but it is very low and fast. Hard to detect at first. What is next?
Bruce
admin says
Check out the datasheet for the chip:
https://www.mouser.com/ds/2/308/mm74c14-1193355.pdf
From there you can see that the chip needs at least 3V. So 2.1 will probably give unreliable results.
bruce hull says
I appreciate your response and that makes sense regarding the voltage level but I had the same results when I substituted a nine volt battery as the power source. My power source is a yard light that comes on at night and goes off during day light hours. The light works fine in the constantly on position but I can’t get the slow on and off that I need for my project. Any suggestions as to possible substitution?
admin says
Are you saying that your circuit is not blinking when you use a 9V battery? One potential error is that the LED draws too much current. Try replacing the resistor in series with the LED with 2000 ohms.
If it’s still not working, measure the battery voltage when it’s connected to the circuit. If it’s less than 9V, you might have a battery that is almost dead. Try replacing with a new one.
bruce hull says
new 9 v battery. I really need to get this to work with the solar panel so the batteries will recharge. the rechargeable batteries are 3.7 V. back to the drawing board.
bruce hull says
So basically for this project to work as designed I need to use the solar panel (Wal Mart outdoor light) Which is powered by a 3.7 Li-ion battery. There’s lots of sunlight in south Mississippi. Will that work with your design?
admin says
The circuit in this article should work fine with voltages above 3V. But you might need to adjust the resistor for the LED.
bruce hull says
It Works but it is blinking a little too fast. What rate resistor do I need to use instead of the 470?
admin says
It’s the 10k resistor or the capacitor you need to change to change the speed. You can for example try doubling the resistor value to 20k.
The 470 resistor sets the brightness of the LED.
Garry Cronin says
hi Oyvind,
I notice in your “Basic Electronic Components” ebook you provide a schematic for a Blinking LED using a 555 Timer IC. Can you compare and contrast the pro’s and con’s of building it that way, compared to the way you show here in this article please?
thanks
– Garry
admin says
The inverter uses less components. But other than that, for blinking an LED they’re pretty much the same.
Robert B Moore says
A step by step assembly video or series of drawings would certainly help this old person. I find it difficult to tell where to hook the components up on the breadboard.
FYI: I hope to use a modified version of this circuit to drive five LEDs on the rear pair of arms on my first quadcopter.
admin says
Hey Robert, I just updated the article with step by step instructions. Hope you’ll find it useful!
ArpitaS says
The video is not there for me.
admin says
It’s a youtube video. And it’s there. Maybe you’re on a network that blocks youtube?
Openplanet says
With all due respect, nowhere do you explain the THEORY OF OPERATION of this circuit! Without this, how can a novice possibly understand HOW and WHY it works?!
I’m a long time electronics hobbyist, so it’s no problem for me. But I’m quite amazed at the absence of an EXPLANATION in what is supposed to be a LEARNING thing.
admin says
This is how to build it. The lessons on how it works can be found here: https://www.build-electronic-circuits.com/free-email-course/